![complex numbers - Show that $\frac{-1+\sqrt{3}i}{2}$ is a cube root of 1? - Mathematics Stack Exchange complex numbers - Show that $\frac{-1+\sqrt{3}i}{2}$ is a cube root of 1? - Mathematics Stack Exchange](https://i.stack.imgur.com/I5IBY.png)
complex numbers - Show that $\frac{-1+\sqrt{3}i}{2}$ is a cube root of 1? - Mathematics Stack Exchange
![SOLVED: Write the cube roots of 64 in standard form: The roots are 1v (Simplify your answer: Express complex numbers in terms of Use comma to separate answers as needed Type your SOLVED: Write the cube roots of 64 in standard form: The roots are 1v (Simplify your answer: Express complex numbers in terms of Use comma to separate answers as needed Type your](https://cdn.numerade.com/ask_previews/d9bac26e-77ec-4da5-95ba-cae2a6c4627b_large.jpg)
SOLVED: Write the cube roots of 64 in standard form: The roots are 1v (Simplify your answer: Express complex numbers in terms of Use comma to separate answers as needed Type your
![Trigonometry/PreCalculus: Finding Cube Roots of Complex Numbers]: What would you solve this problem to get the answer then? : r/HomeworkHelp Trigonometry/PreCalculus: Finding Cube Roots of Complex Numbers]: What would you solve this problem to get the answer then? : r/HomeworkHelp](https://i.redd.it/2vvp4l9minz71.jpg)
Trigonometry/PreCalculus: Finding Cube Roots of Complex Numbers]: What would you solve this problem to get the answer then? : r/HomeworkHelp
If ω is an imaginary number cube root of unity then (1 ω^4)(1 ω^8)(1 ω^22)(1 ω^44)equals to (1)ω^2 (2)ω (3)9 (4)0
![Cube Root of Unity - Property 2 - Complex Numbers - IIT JEE Mathematics Video Lectures - EduGorilla Trends - Videos, News, Career Updates Cube Root of Unity - Property 2 - Complex Numbers - IIT JEE Mathematics Video Lectures - EduGorilla Trends - Videos, News, Career Updates](https://trends.edugorilla.com/wp-content/uploads/sites/8/2018/03/cube-root-of-unity-property-2-complex-numbers-iit-jee-mathematics-video-lectures.jpg)